a.\(\left(x-2\right).\left(x^2+2x+4\right)=x^3-2^3=x^3-8\)
b.\(\left(x+1\right).\left(x^2+2x+1\right)=\left(x+1\right).\left(x+1\right)^2=\left(x+1\right)^3=x^3+3x^2+3x+1\)
Tính:
\(a)\left(-2x^2\right)\cdot\left(3x-4x^3+7-x^2\right)\)
\(b)\left(x+3\right)\cdot\left(2x^2-3x-5\right)\)
\(c)\left(-6x^5+7x^4-6x^3\right):3x^3\)
\(d)\left(9x^2-4\right):\left(3x+2\right)\)
\(e)\left(2x^4-13x^3+15x^2+11x-3\right):\left(x^2-4x-3\right)\)
Tìm x:
\(a,\left(2-x\right)\cdot\left(2x+1\right)>0\)
\(b,\left(2x+3\right)\cdot\left(x+1\right)< 0\)
a,\(\left(x-1\right)\cdot\left(x+2\right)>0\)
b,\(\left(\frac{1}{2}-x\right)\cdot\left(2x-1\right)< 0\)
c,\(\frac{x-1}{2007}+\frac{x-2}{2008}=\frac{x-3}{2009}+\frac{x-4}{2010}\)
d,\(\left(2x-1\right)\cdot\left(2-x\right)>0\)
Tìm x
bạn nào bít thì giúp mình nha!!!
cho đa thức \(f\left(x\right)=4\cdot x^2+3x+1\); \(g\left(x\right)=3x^2-2x+1\); \(k\left(x\right)=7\cdot x^2-35x+42\)
a) tính f(x)-g(x)=h(x)
b) tính nghiệm của h(x) và k(x)
c) tìm gia trị của đa thức h(x) biết:
\(\left(x^2-9\right)^{2021}=\left(\frac{3}{4}-81\right)\cdot\left(\frac{3^2}{5}-81\right)^2\cdot\left(\frac{3^2}{6}-81\right)^3\cdot\cdot\cdot\left(\frac{3^{2020}}{2023}-81\right)^{2020}\)
Tìm x biết
\(x\left(x+1\right)=0\)
\(3x\left(2x-1\right)=0\)
\(\left(x+1\right)\cdot\left(x-2\right)=0\)
\(x^2\cdot\left(x+4\right)=0\)
\(\left(x+1\right)^2\cdot\left(3x-5\right)=0\)
\(x^2+1=0\)
\(3x^2\cdot\left(2x-5\right)^2=0\)
\(1\cdot2\cdot3\cdot.....\cdot100x=0\)
\(\left(\frac{3}{4}\right)^x=1\)
\(\left(\frac{2}{5}\right)^{x+1}=\frac{8}{125}\)
a)\(\frac{3}{2}-\frac{1}{3}\cdot\left(x-\frac{3}{2}\right)-\frac{1}{2}\cdot\left(2\cdot x+1\right)=5\)
b)\(\left(x+\frac{1}{2}\right)\cdot\left(x-\frac{3}{4}\right)=0\)
c)\(2x-3=x+\frac{1}{2}\)
tím số hưũ tỉ x biết
a) \(\frac{-5}{x-3}\)>0
b) |1-2x| >7
c)\(^{\left(x-2\right)\cdot\left(x+2\right)\cdot\left(4-x\right)\cdot\left(x-1\right)^2}\)<= 0
(<= là nhỏ hơn hoặc bằng)
các bác hộ e vs mai e kt dòi :33333
TÌM x
\(\left(\left(\frac{3}{4}\cdot x+5\right)-\left(\frac{2}{3}\cdot x-4\right)-\left(\frac{1}{6}\cdot x+1\right)\right)=\left(\frac{1}{3}\cdot x+4\right)-\left(\frac{1}{3}-3\right)\)
baif1
1)\(x^2=0\)
2)\(x^2=1\)
3)\(x^2=3\)
4)\(x^2=6\)
5)\(x^2=7\left(x>0\right)\)
6)\(x^2=8\left(x< 0\right)\)
7)\(\left(x+1\right)^2=1\)
8)\(\left(x-2\right)^2=4\)
9)\(\left(2x+1\right)^2=9\)
10)\(\left(1-2x\right)^2=25\)
11)\(3\cdot\left(x+2\right)^2=125\)
12)\(4\cdot\left(2x+1\right)^2+5=41\)
13)\(45-2\cdot\left(x-5^2\right)=27\)
14)\(132-5\cdot\left(2x+1\right)^2=-113\)
15)\(253-7\cdot\left(1-3x\right)^2=78\)
cac ban nho lam nhanh giup minh voi minh dang can gap
