Question

Kamen Rider Build - YouTube 

Đăng kí kênh này giúp mk sau đó ib mk nhận 3 t- i - c - k 

Giải pt : x² + 4x + 3 = 0 

Answer 1

\(x^2+4x+3=0\)

\(\Leftrightarrow x^2+x+3x+3=0\)

\(\Leftrightarrow x.\left(x+1\right)+3.\left(x+1\right)=0\)

\(\Leftrightarrow\left(x+1\right).\left(x+3\right)=0\)

\(\Leftrightarrow\orbr{\begin{cases}x+1=0\\x+3=0\end{cases}\Leftrightarrow\orbr{\begin{cases}x=-1\\x=-3\end{cases}}}\)

Vậy  x = -1 hoặc x = -3

Answer 2

Kamen Rider Build - YouTube 

Link đây nhé mn 

Answer 3

Ta có : 

\(x^2+4x+3=0\)

\(\Rightarrow x^2+x+3x+3=0\)

\(\Rightarrow x\left(x+1\right)+3\left(x+1\right)=0\)

\(\Rightarrow\left(x+3\right)\left(x+1\right)=0\)

\(\Rightarrow\orbr{\begin{cases}x+3=0\\x+1=0\end{cases}\Rightarrow\orbr{\begin{cases}x=-3\\x=-1\end{cases}}}\)

Vậy ...

~ 

Answer 4

\(x^2+4x+3=0\)

\(\Rightarrow x^2+2.2x+4-1=0\)

\(\Rightarrow\left(x+2\right)^2=1\)

\(\Rightarrow x+2=\orbr{\begin{cases}1\\-1\end{cases}}\)

\(\Rightarrow x=\orbr{\begin{cases}-1\\-3\end{cases}}\)

Answer 5

\(PT\Leftrightarrow x^2+x+3x+3=0\)

\(\Leftrightarrow x.\left(x+1\right)+3.\left(x+1\right)=0\)

\(\Leftrightarrow\left(x+1\right)\left(x+3\right)=0\)

\(\Leftrightarrow\hept{\begin{cases}x+1=0\\x+3=0\end{cases}\Rightarrow\hept{\begin{cases}x=-1\\x=-3\end{cases}}}\)

Answer 6

kho qua thoi ko tra loi