Vì
\(x+\left(-\frac{31}{12}\right)^2=\left(\frac{49}{12}\right)^2-x\Rightarrow2x=\left(\frac{49}{12}\right)^2-\left(-\frac{31}{12}\right)^2=10\)
=> 2x = 10 => x = 5
Thay x = 5 vào ta có :
\(5+\left(-\frac{31}{12}\right)^2=y^2\Leftrightarrow\frac{1681}{144}=y^2=\left(\frac{41}{12}\right)^2=\left(-\frac{41}{12}\right)^2\)
=> y = 41/12 hoặc y = -41/12
Tìm x,y
x*(x-y)=3/10 và y*(x-y)=–3/20