Question

h(x)=9x²-4

Answer 1

Tìm gì hả bạn ?

Answer 2

ta có:

\(9x^2-4=0\\ 9x^2=4\\ x^2=\dfrac{9}{4}\\ x=\sqrt{\dfrac{9}{4}}=\dfrac{3}{2}\)

\(\Rightarrow\)vậy...

Answer 3

\(\text{Đặt h(x)=0}\)

\(\Rightarrow9x^2-4=0\)

\(\Rightarrow9x^2=0+4=4\)

\(\Rightarrow x^2=4:9=\dfrac{4}{9}\)

\(\Rightarrow x=\sqrt{\dfrac{4}{9}}=\dfrac{2}{3}\)

\(\text{Vậy đa thức h(x) có 1 nghiệm là x=}\dfrac{2}{3}\)