\(2^{2195}=2^{4.548+3}=\left(2^4\right)^{548}.8=\left(...6\right)^{548}.8=\left(...6\right).8=\left(...8\right)\)
=> 2^2195 có t/c là 8
Ta có : \(2^{2192}.2^3=\left(2^4\right)^{548}.2^3=16^{548}.8\) .
Mà : Số có tận cùng là 6 khi nâng lên lũy thừa cũng có tận cùng là 6 .
\(\Leftrightarrow6.8=48\) .
vậy \(2^{2195}\) có tận cùng là 8
ta có: 2195 = 4 x 548 + 3 có dạng 4k+3, vậy:
22195 = 24k+3 = ... 8
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