\(m_{H_2O}=D\cdot V=192.7\left(g\right)\)
\(m_{HCl}=a\left(g\right)\)
\(C\%HCl=\dfrac{a}{a+192.7}\cdot100\%=3.65\%\)
\(\Rightarrow a=7.3\)
\(n_{HCl}=\dfrac{7.3}{36.5}=0.2\left(mol\right)\)
\(V_{HCl}=0.2\cdot22.4=4.48\left(l\right)\)
\(C_{M_{HCl}}=\dfrac{0.2}{0.1927}=1.03\left(M\right)\)