a, PTHH: \(Mg+H_2SO_4\rightarrow MgSO_4+H_2\uparrow\)
b, \(n_{Mg}=\dfrac{m}{M}=\dfrac{4,8}{24}=0,2( mol )\)
Theo PT: \(n_{H_2}=n_{Mg}=0,2(mol)\)
\(V=V_{H_2}=n.22,4=0,2.22,4=4,48(l)\)
c, Theo PT: \(n_{H_2SO_4}=n_{Mg}=0,2(mol)\)
Khối lượng H2SO4 đã dùng là:
\(m_{H_2SO_4}=n.M=0,2.98=19,6(g)\)