a) \(n_{H_2}=\dfrac{14,56}{22,4}=0,65\left(mol\right)\)
Gọi \(\left\{{}\begin{matrix}n_{Al}=x\left(mol\right)\\n_{Zn}=y\left(mol\right)\end{matrix}\right.\Rightarrow27x+65y=21,1\left(1\right)\)
PTHH:
\(2Al+6HCl\rightarrow2AlCl_3+3H_2\)
x----->3x------>x----------->1,5x
\(Zn+2HCl\rightarrow ZnCl_2+H_2\)
y------>2y------->y-------->y
`=> 1,5x + y = 0,65 (2)`
`(1), (2) => x = 0,3; y = 0,2`
`=>` \(\left\{{}\begin{matrix}m_{Al}=0,3.27=8,1\left(g\right)\\m_{Zn}=0,2.65=13\left(g\right)\end{matrix}\right.\)
b) \(n_{HCl}=3.0,3+2.0,2=1,3\left(mol\right)\)
c) \(C\%_{HCl}=\dfrac{1,3.36,5}{500}.100\%=9,49\%\)
d) \(m_{ddspư}=500+21,1-0,65.2=219,8\left(g\right)\)
`=>` \(\left\{{}\begin{matrix}C\%_{AlCl_3}=\dfrac{0,3.133,5}{219,8}.100\%=18,22\%\\C\%_{ZnCl_2}=\dfrac{0,2.136}{219,8}.100\%=12,37\%\end{matrix}\right.\)
