=> \(\left(x+3\right)\left(y+7\right)=\left(y+5\right)\left(x+5\right)\)
=> \(xy+7x+3y+3\cdot7=xy+5y+5x+5\cdot5\)
=> \(xy+7x+3y+21=xy+5y+5x+25\)
=> \(xy+7x+3y+21-xy-5y-5x-25=0\)
=> \(xy+7x+3y-xy-5y-5x=-21+25\)
=> \(2x-2y=4\)
=> \(2\left(x-y\right)=4\)
=> \(x-y=4:2\)
=> \(x-y=2\)
tick cho mình nha