Question

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Answer 1

\(a,=x^3+2x^2-x-2-x^3+8=2x^2-x+6\\ b,=\dfrac{\left(x-2y\right)\left(x+2y\right)}{2\left(x-2y\right)}=\dfrac{x+2y}{2}\\ c,=\dfrac{4xy+x^2-2xy+y^2}{2\left(x-y\right)\left(x+y\right)}\cdot\dfrac{2x}{x+y}-\dfrac{y}{x-y}\\ =\dfrac{x\left(x+y\right)^2}{\left(x-y\right)\left(x+y\right)^2}-\dfrac{y}{x-y}=\dfrac{x}{x-y}-\dfrac{y}{x-y}=1\)