Question

Helpppp

Answer 1

\(PTHH:S+O_2->SO_2\)

ap dung DLBTKL ta co

\(m_S+m_{O_2}=m_{SO_2}\)

\(=>m_{O_2}=m_{SO_2}-m_S\\ =>m_{O_2}=96-48\\ =>m_{O_2}=48\left(g\right)\)

Answer 2

Lưu huỳnh + Khí oxi -> Lưu huỳnh đioxit

PTHH: S + O2 -> SO2

Áp dụng ĐLBTKL :

MS + MO2 -> MSO2

=> 48 + MO2 -> 96

=> MO2= 96-48=48