1.\(\dfrac{5}{7};\dfrac{7}{5};\dfrac{7}{9};\dfrac{9}{7};\dfrac{a+2}{a+2}\)
\(\dfrac{5}{7}< \dfrac{9}{7};\dfrac{7}{5}>\dfrac{7}{9}\); ta đặt a = 0 nên \(\dfrac{0+2}{0+2}=\dfrac{2}{2}=1\)
\(\dfrac{5}{7}< 1;\dfrac{9}{7}>1;\dfrac{7}{5}>1;\dfrac{7}{9}< 1\)
\(\dfrac{5}{7};1;\dfrac{9}{7};\dfrac{7}{9};\dfrac{7}{5}=\dfrac{5}{7};\dfrac{a+2}{a+2};\dfrac{9}{7};\dfrac{7}{9};\dfrac{5}{5}\)
2.\(\dfrac{426+33\times38}{33\times40+360}=\dfrac{426+33\times38}{33\times\left(38+2\right)+360}\)
\(=\dfrac{426+33\times38}{33\times38+\left(33\times2+360\right)}=\dfrac{426+33\times38}{33\times38+426}=1\)