\(\left\{{}\begin{matrix}m_C=85,7\%.28=24\left(g\right)\\m_H=28-24=4\left(g\right)\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}n_C=\dfrac{24}{12}=2\left(mol\right)\\n_H=\dfrac{4}{1}=4\left(mol\right)\end{matrix}\right.\\ CTHH:C_2H_4\)
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\(m_C=\dfrac{85,7}{100}.28=24g\) \(\Rightarrow n_C=\dfrac{24}{12}=2mol\)
\(m_H=\dfrac{14,3}{100}.28=4g\) \(\Rightarrow n_H=\dfrac{4}{1}=4mol\)
\(\Rightarrow CTHH:C_2H_4\)
=> Chọn D
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