Question

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Answer 1

\(a,C=\dfrac{x+2}{\sqrt{x}\left(\sqrt{x}-1\right)}\left(\sqrt{x}-1\right)=\dfrac{x+2}{\sqrt{x}}\\ b,C=\dfrac{x+2}{\sqrt{x}}=\sqrt{x}+\dfrac{2}{\sqrt{x}}\ge2\sqrt{\sqrt{x}\cdot\dfrac{2}{\sqrt{x}}}=2\sqrt{2}\\ C_{min}=2\sqrt{2}\Leftrightarrow x=2\)