Question

Help me, please! 

Tính \(A=\left(2^9+2^7+1\right)\cdot\left(2^{23}-2^{21}+2^{19}-2^{17}+2^{14}-2^{10}+2^9-2^7+1\right)\)

Answer 1

Nhân hết ra rồi rút gọn thôi bạn:

\(A=\left(2^9+2^7+1\right)\left(2^{23}-2^{21}+2^{19}-2^{17}+2^{14}-2^{10}+2^9-2^7+1\right).\)

\(=2^{32}-2^{30}+2^{28}-2^{26}+2^{23}-2^{19}+2^{18}-2^{16}+2^9\)\(+2^{30}-2^{28}+2^{26}-2^{24}+2^{21}-2^{17}+2^{16}-2^{14}+2^7+2^{23}-2^{21}+2^{19}-2^{17}+2^{14}-2^{10}\)\(+2^9-2^7+1\)

\(=2^{32}+\left(2^{23}+2^{23}-2^{24}\right)+\left(2^{18}-2^{17}-2^{17}\right)+\left(2^9+2^9-2^{10}\right)+1=2^{32}+1\)

Answer 2

Thanks Witch Rose_ Phù thủy hoa hồng !