Question

Hãy cho biết số mol của các chất sau:

a) 4 g cacbon ; 62 g photpho ; 42 g sắt.  
b) 3,6 g nước ; 95,48 g khí cacbonic ; 14,625 g muối ăn.
c) 8,96 lít O2 (đktc); 5,6 lít H2 (đktc); 12 lít CO ( đk thường)

Answer 1

\(a,\left\{{}\begin{matrix}n_C=\dfrac{4}{12}=0,25\left(mol\right)\\n_P=\dfrac{62}{31}=2\left(mol\right)\\n_{Fe}=\dfrac{42}{56}=0,75\left(mol\right)\end{matrix}\right.\\ b,\left\{{}\begin{matrix}n_{H_2O}=\dfrac{3,6}{18}=0,2\left(mọl\right)\\n_{CO_2}=\dfrac{95,48}{44}=2,17\left(mol\right)\\n_{NaCl}=\dfrac{14,625}{58,5}=0,25\left(mol\right)\end{matrix}\right.\)

\(c,\left\{{}\begin{matrix}n_{O_2}=\dfrac{8,96}{22,4}=0,4\left(mol\right)\\n_{H_2}=\dfrac{5,6}{22,4}=0,25\left(mol\right)\\n_{CO}=\dfrac{12}{24}=0,5\left(mol\right)\end{matrix}\right.\)

Answer 2

a. \(n_C=\dfrac{4}{12}=\dfrac{1}{3}\left(mol\right)\)

\(n_P=\dfrac{62}{31}=2\left(mol\right)\)

\(n_{Fe}=\dfrac{42}{56}=0,75\left(mol\right)\)

b. \(n_{H_2O}=\dfrac{3.6}{18}=0,2\left(mol\right)\)

\(n_{CO_2}=\dfrac{95.48}{44}=2,17\left(mol\right)\)

\(n_{NaCl}=\dfrac{14.625}{58,5}=0,25\left(mol\right)\)

c. \(n_{O_2}=\dfrac{8.96}{22,4}=0,4\left(mol\right)\)

\(n_{H_2}=\dfrac{5.6}{22,4}=0,25\left(mol\right)\)

\(n_{CO}=\dfrac{12}{24}=0,5\left(mol\right)\)