\(\widehat{SIN}=25^0\)
\(\widehat{JIN}=\widehat{SIN}=25^0\)
\(\widehat{OIJ}=90^0-\widehat{JIN}=90^0-25^0=65^0\)
\(\widehat{IJO}=180^0-\widehat{OIJ}=\widehat{JOI}\)
\(\widehat{IJO}=180^0-65^0-a=115^0-a\)
\(\widehat{MJI}=90^0-\widehat{IJO}=90^0-\left(115^0-a\right)=a-25\)
ta có : \(SI\)vuông góc với \(RJ\)
\(\Rightarrow\widehat{SIJ}+\widehat{RJI}=90^0\)
\(2\widehat{SIN}+2\widehat{MJI}=90^0\)
\(\widehat{SIN}+\widehat{MJI}=45^0\)
\(25^0+a-25^0=45^0\)
\(a=45^0\)
bạn vẽ hộ mình cái hình vẽ
Cảm ơn !