\(\left(x+5\right)^4+\left(x+3\right)^4=16\)
Đặt t = x+ 4 pt ban đầu trở thành
\(\left(t+1\right)^4+\left(t-1\right)^4=16\Leftrightarrow t^4+6t^2-7=0\)
PT \(t^2=7\left(vn\right)\)
\(PTt^2=1\) cho ta nghiệm \(t=1;t=-1\)
\(\Rightarrow PT\) ban đầu \(\Leftrightarrow\orbr{\begin{cases}x+4=-1\\x+4=1\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=-5\\x=-3\end{cases}}\)
GPT: x^5 + x^4 + x^3 + x^2 + x +1 = 0
giúp cần gấp tối nay, xong trước 7h tối
1)Gpt: 2x3 + x + 3 =0
2)Gpt: x3 + x2 - x\(\sqrt{2}\) - 2\(\sqrt{2}=0\)
3)Gpt: 23 -9x + 2 = 0
4)Gpt: x3 - 42 + 7x - 6 = 0
5)Gpt: 2x3 + 7x2 + 7x + 2 = 0
GPT: 48/(x+4) + 48/(x-4) = 5
GPT:
a, (x-1)x(x+1)(x+2)=24
b, \(\frac{x+14}{86}+\frac{x+15}{85}+\frac{x+16}{84}+\frac{x+17}{83}+\frac{x+116}{4}=0\)
\(c,x^4+3x^3+4x^2+3x+1\)
GPT:
(x-7)(x-5)(x-4)(x-2)=72
Gpt : (x+1)^4+(x+3)^4=2
Cám ơn
GPT: x5-x4+3x3+3x2-x+1=0
giai chi tiet gium
GPT:
(3x+4)^2-(3x-1).(3x+1)=49
(x+2).(x^2-2x+4)-x.(x+3).(x-3)
Gpt:
x^3- x =0
(x^3-4x^2)-(x-4) = 0
