đặt x-1=a ĐKXĐ tự tìm
\(\sqrt{2a+3}-\sqrt{3a-3}=a\Leftrightarrow\sqrt{2a+3}=a+\sqrt{3a-3}\)
bình phương 2 vế ta có :\(2a+3=a^2+3a-3+2a\sqrt{3a-3}\Leftrightarrow-a-1=2\sqrt{3a-3}\)
mik giải sai 3a-3 thành 3a+3, sau đó bình phương lên giải nghiệm
gpt:
\(\sqrt{2x^2-1}+\sqrt{x^2-3x-2}=\sqrt{2x^2+2x+3}+\sqrt{x^2-x+2}\)
GPT : \(\sqrt{3x^2+3x}+\sqrt{x-x^2}=2x+1\)
GPT:\(\sqrt{3x+1}+x^2+2x=3+\sqrt{2x+2}\)
GPT
\(x^2+6x+1=\left(2x+1\right)\sqrt{x^2+2x+3}\)3
\(\sqrt{3x-2}-\sqrt{x-1}=2x^2-x-3\)
gpt:\(\sqrt{3x^2+6x+4}+\sqrt{2x^2+4x+11}=\left(1-x\right)\left(x+3\right)\)
\(\sqrt{3x^2+6x+7}+\sqrt{5x^2+10x+21}=5-x^2-2x\)
\(\sqrt{x^2-x+2}+\sqrt{x^2-3x+6}=2x\)
Gpt
a)\(\left(4x-1\right)\sqrt{x^2+1}=2x^2+2x+1\)
b) \(x^2-3x+2=\sqrt{x+1}\)
Gpt: \(\sqrt{\frac{1-2x}{x}}=\frac{3x+x^2}{x^2+1}\)
gpt bằng pp đặt ẩn phụ k hoàn toàn:
1, \(2\sqrt{2x+4}+4\sqrt{2-x}=\sqrt{9x^2+16}\)
2, \(\left(3x+2\right)\sqrt{2x-3}=2x^2+3x-6\)
GPT: \(\sqrt{2x-1}+x^2-3x+1=0\)
