À nhầm mình làm lại nha:
\(\Leftrightarrow\frac{x-2}{x^2-4}-\frac{2x}{x^2-4}=\frac{x^2-4}{x^2-4}\)ĐKXĐ:x khác +-2
\(\Leftrightarrow\frac{x-2-2x-x^2+4}{x^2-4}=0\)
\(\Rightarrow-x^2-x+2=0\)
\(\Leftrightarrow-x^2-2x+x+2=0\)
\(\Leftrightarrow-x\left(x+2\right)+\left(x+2\right)=0\)
\(\Leftrightarrow\left(1-x\right)\left(x+2\right)=0\)
\(\Leftrightarrow1-x=0ho\text{ặc} x+2=0\)
\(\Leftrightarrow x=1 ho\text{ặc} x=-2\left(lo\text{ại}\right)\)
Vậy pt trên có nghiệm là x=1
\(\frac{1}{x+2}\) -\(\frac{2x}{x^2-4}\)=1
<=>\(\frac{x-2-2x}{\left(x+2\right)\left(x-2\right)}\)=1
<=>\(\frac{-\left(x+2\right)}{\left(x+2\right)\left(x-2\right)}\)=1
<=>\(\frac{-1}{x-2}\)=1
=>x-2=-1
x=(-1)+2
Vậy x=1
