Because BD is bisector, we have: \(\frac{DC}{AD}=\frac{BC}{AB}=\frac{7}{5}\)
On the other hand, CD - AD = 1.
Hence we have \(\hept{\begin{cases}CD=3,5\\AD=2,5\end{cases}}\)
Thus the length of AC equal : 3,5 + 2,5 = 6 (cm).
Given a square with the length of one side is 8 cm and a isosceles triangle with the length of its base is 12 cm. If the area of the square is equal to the area of the isosceles triangle then what is the length of the height of the isosceles triangle, in cm?
Given the right triangle ABC (A^ = 90o), BD is the bisector of the angle at B ( D of AC ). If AD = 6cm and AB = 12cm then the area of the right triangle ABC is ...... cm2.
Given the right triangle ABC (A^ = 90o), BD is the bisector of the angle at B ( D of AC ). If AD = 6cm and AB = 12cm then the area of the right triangle ABC is ...... cm2.
Given the right triangle ABC (A^ = 90o), BD is the bisector of the angle at B ( D of AC ). If AD = 6cm and AB = 12cm then the area of the right triangle ABC is ...... cm2.
Given the point C on the segment AB such that the ratio of AC to CB is 3:7. Find the length of BC if the length of AB is 30 cm.
Answer: The length of BC is ...... cm
given isosceles trapezoid ABCD (AB//CD), AC is perpendicular to BD and the length of the height of the ABCD is 7 cm. What is the area of the isosceles trapezoid ABCD?
The area of an isosceles right triangle is 9 cm2.
Find the length of its hypotenuse.
Answer: The length of its hypotenuse is .... cm.
The area of an isosceles right triangle is 9 cm2.
Find the length of its hypotenuse.
Answer: The length of its hypotenuse is .... cm.
The right triangle FGH has mid-segments of length 10 cm, 24cm and 26cm. What is the area of triangle FGH
