Bài 2
\(a,=\dfrac{5}{7}\left(\dfrac{12}{11}+\dfrac{27}{11}-\dfrac{17}{11}\right)\\ =\dfrac{5}{7}.2=\dfrac{10}{7}\\ b,=\dfrac{3}{5}.\left(-\dfrac{5}{7}-\dfrac{3}{7}-\dfrac{6}{7}\right)\\ =\dfrac{3}{5}.\left(-2\right)\\ =-\dfrac{6}{5}\\ c,=\dfrac{1}{3}\left(\dfrac{4}{5}+\dfrac{6}{5}-\dfrac{4}{3}\right)\\ =\dfrac{1}{3}.\left(\dfrac{2.3-4}{3}\right)\\ =\dfrac{1}{3}.\dfrac{2}{3}\\ =\dfrac{2}{9}\\ d,=-\dfrac{5}{7}.\left(\dfrac{2}{11}+\dfrac{9}{11}\right)\\ =-\dfrac{5}{7}.1=-\dfrac{5}{7}\)