1)
$n_{Na_2O} = \dfrac{12,4}{62} = 0,2(mol)$
$Na_2O + H_2O \to 2NaOH$
$n_{NaOH} = 2n_{Na_2O} = 0,4(mol)$
$m_{NaOH} = 0,4.40 = 16(gam)$
2)
$HCl + NaOH \to NaCl + H_2O$
$n_{HCl} = n_{NaOH} = 0,4(mol)$
$C\%_{HCl} = \dfrac{0,4.36,5}{500}.100\% = 2,92\%$
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