\(\frac{x+4}{2009}+\frac{x+3}{2010}=\frac{x+2}{2011}+\frac{x+1}{2012}\)\(\Leftrightarrow\)\(\left(\frac{x+4}{2009}+1\right)+\left(\frac{x+3}{2010}+1\right)=\left(\frac{x+2}{2011}+1\right)+\left(\frac{x+1}{2012}+1\right)\)
\(=\frac{x+2013}{2009}+\frac{x+2013}{2010}=\frac{x+2013}{2011}+\frac{x+2013}{2012}\)
Biểu thức trên chi thỏa mãn khi x+2013=0
\(\Rightarrow x=-2013\)
mk nghĩ là -2013 vì nếu thay x=-2013 vào thì các phân số sẽ bằng -1.
nếu cộng lại thì đc -2
k nhé
k cho mik nhé. Thsssssssssssssssss!!!!!!!!!!!!!!!!!!
\(\frac{x+4}{2009}+\frac{x+3}{2010}-\frac{x+2}{2011}-\frac{x+1}{2012}=0\)
\(\left(\frac{x+4}{2009}+1\right)+\left(\frac{x+2003}{2010}+1\right)-\left(\frac{x+2}{2011}+1\right)-\left(\frac{x+1}{2012}+1\right)=0\)
\(\frac{x+2013}{2009}+\frac{x+2013}{2010}-\frac{x+2013}{2011}-\frac{x+2013}{2012}=0\)
\(\left(x+2013\right)\left(\frac{1}{2009}+\frac{1}{2010}+\frac{1}{2011}+\frac{1}{2012}\right)=0\)
\(x+2013=0\left(vì\frac{1}{2009}+\frac{1}{2010}+\frac{1}{2011}+\frac{1}{2012}\ne0\right)\)
x=-2013
