Question

Giúp toii nhó ?!!

Answer 1

\(n_{Zn}=\dfrac{26}{65}=0.4\left(mol\right)\)

\(Zn+2HCl\rightarrow ZnCl_2+H_2\)

\(0.4................................0.4\)

\(V_{H_2}=0.4\cdot22.4=8.96\left(l\right)\)

Answer 2

a) $Zn + 2HCl \to ZnCl_2 + H_2$
b) n H2 = n Zn = 26/65 = 0,4(mol)

V H2 = 0,4.22,4 = 8,96 lít

Answer 3

a ) PTHH : Zn +2HCl → ZnCl₂ + H₂

b) Ta có : `m_(Zn) = 26 (g)→n_(Zn) = 0,4 (mol)`

`→ nH_2 = 0,4 (mol)`

`V_(H_2)=0,4.22,4 = 8,96 (l)`