|x-2|=2/3 hoặc -2/3
th1 x-2=2/3
x=2/3+2
x=8/3
th2 x-2=-2/3
x=-2/3+2
x=4/3
chúc bạn học tốt!
Ta có :
\(\left|x-2\right|=\dfrac{2}{3}+0\)
\(\left|x-2\right|=\dfrac{2}{3}\)
\(\left\{{}\begin{matrix}x-2=\dfrac{2}{3}\\x-2=\dfrac{-2}{3}\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}x=\dfrac{8}{3}\\x=\dfrac{4}{3}\end{matrix}\right.\)
c) |x-2|-\(\dfrac 2 3\)=0
=>|x-2|=\(\dfrac 2 3\)
=>x=\(\dfrac 2 3\)hoặc x=\(\dfrac {-2} 3\)
\(\left|x-2\right|-\dfrac{2}{3}=0\)
\(\left|x-2\right|\) \(=0+\dfrac{2}{3}=\dfrac{2}{3}\)
\(\text{Vậy }x-2=\dfrac{2}{3}\)
\(x\) \(=\dfrac{2}{3}+2=\dfrac{8}{3}\)
\(\text{hoặc }x-2=\dfrac{-2}{3}\)
\(x\) \(=\left(\dfrac{-2}{3}\right)+2=\dfrac{4}{3}\)
\(\Rightarrow x\in\left\{\dfrac{8}{3};\dfrac{4}{3}\right\}\)
