`@` `\text {Ans}`
`\downarrow`
`3,`
`a)`
\(\dfrac{5}{2}\times\dfrac{1}{3}+\dfrac{1}{4}=\dfrac{5}{6}+\dfrac{1}{4}=\dfrac{13}{12}\)
`b)`
\(\dfrac{6}{5}+\dfrac{3}{5}\div2=\dfrac{6}{5}+\dfrac{3}{10}=\dfrac{3}{2}\)
`c)`
\(\left(\dfrac{6}{15}+\dfrac{3}{15}\right)\times\dfrac{4}{9}=\dfrac{9}{15}\times\dfrac{4}{9}=\dfrac{4}{15}\)
`d)`
\(\dfrac{3}{7}\times\left(\dfrac{9}{11}-\dfrac{2}{11}\right)=\dfrac{3}{7}\times\dfrac{7}{11}=\dfrac{3}{11}\)
`4,`
`a)`
\(\dfrac{3}{7}+\dfrac{4}{9}+\dfrac{4}{7}+\dfrac{5}{9}=\left(\dfrac{3}{7}+\dfrac{4}{7}\right)+\left(\dfrac{4}{9}+\dfrac{5}{9}\right)=\dfrac{7}{7}+\dfrac{9}{9}=1+1=2\)
`b)`
\(\dfrac{1}{5}+\dfrac{4}{11}+\dfrac{4}{5}+\dfrac{7}{11}=\left(\dfrac{1}{5}+\dfrac{4}{5}\right)+\left(\dfrac{4}{11}+\dfrac{7}{11}\right)=\dfrac{5}{5}+\dfrac{11}{11}=1+1=2\)
`c)`
\(\dfrac{1}{15}+\dfrac{4}{15}+\dfrac{5}{18}+\dfrac{7}{18}=\left(\dfrac{1}{15}+\dfrac{4}{15}\right)+\left(\dfrac{5}{18}+\dfrac{7}{18}\right)=\dfrac{1}{3}+\dfrac{2}{3}=1\)
`d)`
\(\dfrac{1}{8}+\dfrac{1}{12}+\dfrac{3}{8}+\dfrac{5}{12}=\left(\dfrac{1}{12}+\dfrac{5}{12}\right)+\left(\dfrac{1}{8}+\dfrac{3}{8}\right)=\dfrac{1}{3}+\dfrac{1}{2}=\dfrac{5}{6}\)





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