`@` `\text {Ans}`
`\downarrow`
`1,`
`a)`
\(\dfrac{7}{19}+\dfrac{12}{19}=\dfrac{7+12}{19}=\dfrac{19}{19}=1\)
`b)`
\(\dfrac{5}{13}+\dfrac{4}{13}=\dfrac{5+4}{13}=\dfrac{9}{13}\)
`c)`
\(\dfrac{24}{11}-\dfrac{13}{11}=\dfrac{24-13}{11}=\dfrac{11}{11}=1\)
`d)`
\(\dfrac{35}{8}-\dfrac{19}{8}=\dfrac{35-19}{8}=\dfrac{16}{8}=2\)
`2,`
`a)`
\(\dfrac{3}{7}+\dfrac{5}{4}=\dfrac{12}{28}+\dfrac{35}{28}=\dfrac{12+35}{28}=\dfrac{47}{28}\)
`b)`
\(\dfrac{4}{5}+\dfrac{12}{10}=\dfrac{8}{10}+\dfrac{12}{10}=\dfrac{8+12}{10}=\dfrac{20}{10}=2\)
`c)`
\(\dfrac{12}{8}-\dfrac{4}{9}=\dfrac{108}{72}-\dfrac{32}{72}=\dfrac{76}{72}=\dfrac{19}{18}\)
`d)`
\(\dfrac{2}{7}-\dfrac{3}{14}=\dfrac{4}{14}-\dfrac{3}{14}=\dfrac{1}{14}\)
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