2/5 + 3/5 : (3/5 + -2/3) - 3 1/2
⇔ 2/5 + 3/5 : (-1/15) - 7/2
⇔ 2/5 + (-9) - 7/2
⇔ -43/5 - 7/2
⇔ -121/10
Vậy ...
\(d,\)\(\dfrac{2}{5}+\dfrac{3}{5}:\left(\dfrac{3}{5}+\dfrac{-2}{3}\right)-3\dfrac{1}{2}\)
\(=\dfrac{2}{5}+\dfrac{3}{5}:\dfrac{4}{5}-\dfrac{7}{2}\)
\(=\dfrac{2}{5}+\dfrac{3}{4}-\dfrac{7}{2}\)
\(=\dfrac{23}{20}-\dfrac{7}{2}\)
\(=\dfrac{-3}{5}\)
\(#Thư\)
d)\(=\dfrac{2}{5}+\dfrac{3}{5}\times\dfrac{5}{4}-\dfrac{2}{7}=\dfrac{2}{5}+\dfrac{3}{4}-\dfrac{7}{2}=\dfrac{23}{20}-\dfrac{7}{2}=-\dfrac{3}{5}\)
giúp mk với mn ơi

