c/ \(\dfrac{-6}{7}\)= \(\dfrac{x}{-14}\)
x = \(\dfrac{\left(-6\right).\left(-14\right)}{7}\)= 12
d/ \(\dfrac{-8}{3}\)= \(\dfrac{-16}{x}\)
x = \(\dfrac{3.\left(-16\right)}{-8}\)= \(\dfrac{9}{4}\)= 2,25
\(c.\dfrac{-6}{7}=\dfrac{x}{-14}\Leftrightarrow x=\dfrac{-6.\left(-14\right)}{7}=12\\ d.\dfrac{-8}{3}=\dfrac{-16}{x}\Leftrightarrow x=\dfrac{3.\left(-16\right)}{-8}=6\)
\(\dfrac{-6}{7}=\dfrac{x}{-14}\)
\(\left(-6\right).\left(-14\right)=7x\)
84=7x
x=84:7
x=12
Vậy ....
d,\(\dfrac{-8}{3}=\dfrac{-16}{x}\)
(-8)x=(-16).3
(-8x)=-48
x = (-48):(-8)
x = 6
Vậy x = 6
c.\(\dfrac{-6}{7}=\dfrac{x}{-14}\) \(\dfrac{-6}{7}=\dfrac{x}{-7}\) chuyển dấu =>x = -6
c.\(\dfrac{-6}{7}\) = \(\dfrac{x}{-14}\)
x = \(\dfrac{\left(-6\right).\left(-14\right)}{7}\) = 12
d/ \(\dfrac{-8}{3}\)= \(\dfrac{-16}{x}\)
x = \(\dfrac{3.\left(-16\right)}{-8}\) = 6
c) \(\dfrac{-6}{7}=\dfrac{x}{-14}\)
\(\Rightarrow x=\dfrac{-6.-14}{7}=12\)
d) \(\dfrac{-8}{3}=\dfrac{-16}{x}\)
\(\Rightarrow x=\dfrac{-16.3}{-8}=6\)