Các câu hỏi tương tự
Tính
\(M=1+\frac{1}{2}\left(1+2\right)+\frac{1}{3}\left(1+2+3\right)+\cdot\cdot\cdot\cdot+\frac{1}{16}\left(1+2+3+\cdot\cdot\cdot16\right)\)
giúp mình với
Tính A=\(1+\frac{1}{2}\cdot\left(1+2+3\right)+\frac{1}{4}\cdot\left(1+2+3+4\right)+.........+\frac{1}{16}\cdot\left(1+2+3+.........+16\right)\)
Tính:
a) M=\(\frac{2\cdot2012}{1+\frac{1}{1+2}+\frac{1}{1+2+3}+\frac{1}{1+2+3+4}+...+\frac{1}{1+2+3+...+20012}}\)
b) N= \(1+\frac{1}{2\cdot\left(1+2\right)}+\frac{1}{3\cdot\left(1+2+3\right)+}+\frac{1}{4}\cdot\left(1+2+3+4\right)\)\(+...+\frac{1}{16}\cdot\left(1+2+3+4+...+16\right)\)
Giúp nha mình tick
Tính
a)\(\left(-\frac{1}{4}\right)^2+\frac{3}{8}\cdot\left(-\frac{1}{6}\right)-\frac{3}{16}:\left(-\frac{1}{2}\right)\)
b)\(-\frac{1}{2}:\left(1-\frac{3}{4}\right)^2-\frac{2}{3}:\frac{9}{8}-\left(\frac{9}{8}\right)^0\)
c)\(4\cdot\left(-\frac{1}{2}\right)^3+2\cdot\left(-\frac{1}{2}\right)^2-3\cdot\left(-\frac{1}{2}\right)+2006^0\)
Cho: P = \(2^{2018}-2^{2017}-2^{2016}-...-2-1\)
Q = \(1+\frac{1}{2}\cdot\left(1+2\right)+\frac{1}{3}\cdot\left(1+2+3\right)+\frac{1}{4}\cdot\left(1+2+3+4\right)+...+\frac{1}{16}\cdot\left(1+2+3+...+16\right)\)
Tính : \(S=\frac{P}{Q}\)
A)2009^{left(1000-1^3right)cdotleft(1000-2^3right)cdot...cdotleft(1000-15^3right)}B)left(frac{1}{125}-frac{1}{1^3}right)cdotleft(frac{1}{125}-frac{1}{2^3}right)cdot...cdotleft(frac{1}{125}-frac{1}{25^3}right)C)left(frac{1}{38}-1right)cdotleft(frac{1}{37}-1right)cdotleft(frac{1}{36}-1right)cdot...cdotleft(frac{1}{2}-1right)HELP ME!!!!!!!!!!!!!!!!!!!
Đọc tiếp
A)\(2009^{\left(1000-1^3\right)\cdot\left(1000-2^3\right)\cdot...\cdot\left(1000-15^3\right)}\)
B)\(\left(\frac{1}{125}-\frac{1}{1^3}\right)\cdot\left(\frac{1}{125}-\frac{1}{2^3}\right)\cdot...\cdot\left(\frac{1}{125}-\frac{1}{25^3}\right)\)
C)\(\left(\frac{1}{38}-1\right)\cdot\left(\frac{1}{37}-1\right)\cdot\left(\frac{1}{36}-1\right)\cdot...\cdot\left(\frac{1}{2}-1\right)\)
HELP ME!!!!!!!!!!!!!!!!!!!
\(\left[6\cdot\left(-\frac{1}{3}\right)^2-3\cdot\left(-\frac{1}{3}\right)+1\right]:\left(-\frac{1}{3}-1\right)\)
\(\frac{\left(\frac{2}{3}\right)^3\cdot\left(-\frac{3}{4}\right)^2\cdot\left(-1\right)^{2003}}{\left(\frac{2}{5}\right)^2\cdot\left(-\frac{5}{12}\right)^3}\)
\(1+\frac{1}{2}\cdot\left(1+2\right)+\frac{1}{3}\cdot\left(1+2+3\right)+\frac{1}{4}\cdot\left(1+2+3+4\right)+\cdot\cdot\cdot\frac{1}{20}\cdot\left(1+2+3+4+....+20\right)\)
Tính các tích sau: với n là số tự nhiên, n<3
a) \(\left(1-\frac{1}{2}\right)\cdot\left(1-\frac{1}{3}\right)\cdot\left(1-\frac{1}{4}\right)\cdot...\cdot\left(1-\frac{1}{n}\right)\)
b) \(\left(1-\frac{1}{2^2}\right)\cdot\left(1-\frac{1}{3^2}\right)\cdot\left(1-\frac{1}{4^2}\right)\cdot...\cdot\left(1-\frac{1}{n^2}\right)\)