\(-\left(-a+b+c\right)+\left(b-c-1\right)=\left(b-c+6\right)-\left(7-a+b\right)+c\)
\(a-b-c+b-c-1=b-c+6-7+a-b+c\)
\(a-2c-1=a-1\)
\(-2c\ne0\)hay đẳng thức ko xảy ra
Các câu hỏi tương tự
Bai 1: Tinh nhanh:a, -69+53+46+(-14)+78 b, 13-12+11+10-9+8-7-6+5-4+3+2-1Bai 2: a,Tim gia tri nho nhat cua bieu thuc: A |x+19|+|y-5|+1890 b, Tim gia tri lon nhat cua bieu thuc: B -|x-7|-|y+13|+1945Bai 3: Tim x,y thuoc Z biet: a, xy-3x -19 b, 3x+4y-xy 16Bai 4: Tim x thuoc Z biet: a, x.(x+3) 0 b, (x-2) (5-x) 0 c, (x+1) (x2+1) 0 d, -12 (x-5)+7 (3-x) 5 e, 30 (x+2)-6 (x-5)-24x 100 f, (x+1)+(x+3)+(x+5)+. . .+(x+99) 0 ...
Đọc tiếp
Bai 1: Tinh nhanh:
a, -69+53+46+(-14)+78 b, 13-12+11+10-9+8-7-6+5-4+3+2-1
Bai 2: a,Tim gia tri nho nhat cua bieu thuc: A= |x+19|+|y-5|+1890
b, Tim gia tri lon nhat cua bieu thuc: B= -|x-7|-|y+13|+1945
Bai 3: Tim x,y thuoc Z biet: a, xy-3x= -19 b, 3x+4y-xy= 16
Bai 4: Tim x thuoc Z biet: a, x.(x+3)= 0 b, (x-2) (5-x)= 0 c, (x+1) (x2+1)= 0
d, -12 (x-5)+7 (3-x)= 5 e, 30 (x+2)-6 (x-5)-24x= 100 f, (x+1)+(x+3)+(x+5)+. . .+(x+99)= 0
Minh xin cam on truoc ! THANK YOU
Tim x thuoc Z
a}[x+1]+[x+2]+[x+3]+...............+[x+99]=0
b}[x-3]+[x-2]+[x-1]+.................+10+11=11
1 )Tim x, y thuoc Z
x + y = x.y
2) Tim x thuoc Z
(x + 1)+(x+3)+(x+5)+...+(x+99)=0(x-3)+(x-2)+(x-1)+...+10+11=11-12(x-5)+7(3-x)=530(x+2)-6(x-5)-24x=100
Tim x thuoc Z :
a, -8.( 2 . x - 1 ) + 4 ( 1 - x ) = 16
b, x ( x - 2019 ) - x + 2019 = 0
c, ( x + 5 ) . ( 3 x - 12 ) < 0
giup minh bai nay voi
1. Tìm x thuộc Z, biết
a)21-(x-3)<0
b)(-2).(7+x)<0
C)(x-1).(x+2)<0
2.Tính tổng
A=0-1+2-3+4-5+6-7+.........+2017-2018
B=1-3+5-7+9-11+....+2005-2007
C=1+2+3-4-5-6+7+8+9-10-11-12+.....+97+98+99-100-101-102
Tim x
A, 6 x + x = 5^11 : 5^9 +3^1
B, 7 x - x = 5^21 : 5^19 + 3 . 2^2 -7^0
C, 7 x - 2x = 6^17 : 6^15 + 44 : 11
giup minh nhe . Thank you
tìmx biết:
a)(x+1)+(x+3)+(x+5)+....(x+99)=0
b)(x-3)+(x-2)+(x-1)+...+10+11=11
giup mk voi .mk dang can gấp .
please.
timx,y thuoc z biet
a,(x+1)+(x+3)+(x+5)+...+(x+99)=0 b,(x-3)+(x-2)+(x-1)+...+10+11=11
c,(x-3)+(2x+1)=7 s,(x+3).(x2+1)=0
a/[x-2][7-x] > 0 . tim x thuoc Z
b/[x mu 2+13][x mu 2-17] > 0 . tim x thuoc Z
c/[x mu 2-13][x mu 2-17] <0 . tim x thuoc Z
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