PTHH: \(CaCO_3+2CH_3COOH\rightarrow\left(CH_3COO\right)_2Ca+CO_2\uparrow+H_2O\)
a+b) Ta có: \(n_{CH_3COOH}=\dfrac{200\cdot15\%}{60}=0,5\left(mol\right)\)
\(\Rightarrow n_{CaCO_3}=n_{CO_2}=0,25\left(mol\right)\) \(\Rightarrow\left\{{}\begin{matrix}m_{CaCO_3}=0,25\cdot100=25\left(g\right)\\V_{CO_2}=0,25\cdot22,4=5,6\left(l\right)\end{matrix}\right.\)
c) Theo PTHH: \(n_{\left(CH_3COO\right)_2Ca}=n_{CO_2}=0,25\left(mol\right)\) \(\Rightarrow\left\{{}\begin{matrix}m_{\left(CH_3COO\right)_2Ca}=0,25\cdot158=39,5\left(g\right)\\m_{CO_2}=0,25\cdot44=11\left(g\right)\end{matrix}\right.\)
Mặt khác: \(m_{dd}=m_{CaCO_3}+m_{ddCH_3COOH}-m_{CO_2}=214\left(g\right)\)
\(\Rightarrow C\%_{\left(CH_3COO\right)_2Ca}=\dfrac{39,5}{214}\cdot100\%\approx18,46\%\)
