\(\dfrac{2}{5}+\dfrac{3}{10}-\dfrac{1}{2}=\dfrac{4}{10}+\dfrac{3}{10}-\dfrac{1}{2}=\dfrac{7}{10}-\dfrac{1}{2}=\dfrac{7}{10}-\dfrac{5}{10}=\dfrac{2}{10}=\dfrac{1}{5}\)
b) \(\dfrac{2}{5}+\dfrac{3}{10}-\dfrac{1}{2}=\dfrac{4}{10}+\dfrac{3}{10}-\dfrac{5}{10}=\dfrac{4+3-5}{10}=\dfrac{2}{10}=\dfrac{1}{5}\)
c) \(\dfrac{8}{11}+\dfrac{8}{33}\times\dfrac{3}{4}=\dfrac{8}{11}+\dfrac{24}{132}=\dfrac{8}{11}+\dfrac{2}{11}=\dfrac{10}{11}\)
b)
\(=\dfrac{4}{10}+\dfrac{3}{10}-\dfrac{5}{10}=\dfrac{2}{10}=\dfrac{1}{5}\)
c)
\(=\dfrac{8}{11}+\dfrac{2}{11}=\dfrac{10}{11}\)
`2/5 + 3/10 - 1/2 = 4/5 + 3/10 - 5/10 = 1/5`
\(b.\dfrac{2}{5}+\dfrac{3}{10}-\dfrac{1}{2}=\dfrac{4}{10}+\dfrac{3}{10}-\dfrac{1}{2}=\dfrac{7}{10}-\dfrac{1}{2}=\dfrac{7}{10}-\dfrac{5}{10}=\dfrac{2}{10}=\dfrac{1}{5}\)
\(c.\dfrac{8}{11}+\dfrac{8}{33}\times\dfrac{3}{4}=\dfrac{8}{11}+\dfrac{2}{11}=\dfrac{10}{11}\)




