ta có :
HCOOH+Na->HCOONa+1\2H2
x-------------------------------------0,5x
CH3COOH+Na->CH3COONa+1\2H2
y-------------------------------------------0,5y
=>Ta có :\(\left\{{}\begin{matrix}46x+60y=11,52\\0,5x+0,5y=0,107\end{matrix}\right.\)
=>x=0,094 mol, y=0,119 mol
=>m HCOOH=0,094.46=4,324g
=>m CH3COOH=7,196g
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