C2H5OH+Na->C2H5ONa+1\2H2
x---------------------------------------1\2x
C6H5OH+Na->C6H5ONa+1\2H2
y-------------------------------------1\2y
=>Ta có :\(\left\{{}\begin{matrix}46x+94y=18,7\\0,5x+0,5y=0,125\end{matrix}\right.\)
=>x=0,1 ,y=0,15 mol
=>m C2H5OH=0,1.46=4,6g
=>m C6H5OH=18,7-4,6=14,1g
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