Câu 3:
\(a,P=\dfrac{1+\sqrt{x}}{\sqrt{x}\left(\sqrt{x}+1\right)}\cdot\dfrac{\sqrt{x}+1}{2}=\dfrac{\sqrt{x}+1}{2\sqrt{x}}\\ b,x=9\Leftrightarrow P=\dfrac{3+1}{2\cdot3}=\dfrac{4}{6}=\dfrac{2}{3}\\ c,P=\dfrac{\sqrt{x}+1}{2\sqrt{x}}=\dfrac{1}{2}+\dfrac{1}{2\sqrt{x}}>\dfrac{1}{2}\left(\dfrac{1}{2\sqrt{x}}>0\right)\)
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