bai toan kiem tra15 phut truong minh do. the nao co kho ko giup to voi cac ban
\(4n+1⋮\left(n-3\right)\)
\(\Rightarrow4.\left(n-3\right)+13⋮\left(n-3\right)\)
\(\Rightarrow13⋮\left(n-3\right)\Rightarrow\left(n-3\right)\inƯ\left(13\right)=\left\{\pm1;\pm13\right\}\)
\(\Rightarrow n\in\left\{4;2;16;-10\right\}\)
easy!
\(4n+1⋮n-3\)
\(\Rightarrow4\left(n-3\right)+13⋮n-3\)
\(\Rightarrow13⋮n-3\)
\(\Rightarrow n-3\in\left\{13;1;-13;-1\right\}\)
\(\Rightarrow n\in\left\{16;4;-10;2\right\}\)
Ta có : \(4n+1⋮n-3\)
\(\Rightarrow4n-12+13⋮n-3\)
\(\Rightarrow4\left(n-3\right)+13⋮n-3\)
Mà : \(4\left(n-3\right)⋮n-3\)suy ra : \(13⋮n-3\)
\(\Rightarrow n-3\inƯ\left(13\right)=\left\{-13;-1;1;13\right\}\)
\(\Rightarrow n\in\left\{-13;2;4;16\right\}\)
