\(\left(x^4\right)^2=\frac{x^{12}}{x^5}\)
\(x^8=x^{12}:x^5\)
\(x^8=x^7\)
=> x8 - x7 = 0
x7.(x-1) = 0
=> x7 = 0=> x = 0
x-1 = 0 => x = 1
KL: x = 1 hoặc x = 0
\(\frac{x}{\left(x^4\right)^2}=\frac{x^{12}}{x^5}\)
=>\(\frac{x}{x^8}=x^7\)
=>\(\frac{1}{x^7}=x^7\)
=>\(1=x^7.x^7\)
=>\(1^{14}=x^{14}\)
=>\(x=1\)
Bài này \(x^5\rightarrow x^4\) mới đúng chứ?
\(\frac{x^{12}}{x^4}=x^{\left(12-4\right)}=x^8=\left(x^4\right)^2\)
\(ĐK:x^5\ne0\)
\(x\ne0\)
\(\left(x^4\right)^2=\frac{x^{12}}{x^5}\)
\(x^8=x^7\)
\(x^8-x^7=0\)
\(x^7\cdot\left(x-1\right)=0\)
\(\orbr{\begin{cases}x^7=0\\x-1=0\end{cases}}\)
\(\orbr{\begin{cases}x=0\left(l\right)\\x=1\left(n\right)\end{cases}}\)
