Question

Giúp mình từ k4-k12

Answer 1

k4 = \(\dfrac{1}{2}-\dfrac{-2}{3}+\dfrac{5}{6}\)
     = \(\dfrac{7}{6}+\dfrac{5}{6}\)= \(\dfrac{11}{6}\)
k6= \(-\dfrac{2}{9}.\dfrac{5}{13}+\dfrac{-2}{9}.\dfrac{8}{13}+1\dfrac{9}{9}\)
    = \(-\dfrac{2}{9}.\left(\dfrac{5}{13}+\dfrac{8}{13}\right).\dfrac{11}{9}\)
    = \(-\dfrac{2}{9}.1.\dfrac{11}{9}\)=\(-\dfrac{2}{9}.\dfrac{11}{9}\)=\(-\dfrac{2}{9}\)
 

 

Answer 2

\(k7=\dfrac{-3}{20}.\dfrac{11}{4}+\dfrac{3}{20}.\dfrac{11}{4}\)
     \(=-\dfrac{3}{20}+\dfrac{3}{20}.\dfrac{11}{4}\)= 0
k9 =\(=-\dfrac{5}{9}-\dfrac{-1}{10}\)= \(-\dfrac{41}{90}\)

Answer 3

k10= \(\dfrac{2}{3}+\dfrac{5}{8}=\dfrac{31}{24}\)
k11 = \(\dfrac{2}{5}+\dfrac{-27}{35}=-\dfrac{13}{35}\)