\(x^2+4x-192\)
\(=\left(x^2-12x\right)+\left(16x-192\right)\)
\(=x\left(x-12\right)+16\left(x-12\right)\)
\(=\left(x+16\right)\left(x-12\right)\)
\(x^2\)+4x−192
=(\(x^2\)−12x)+(16x−192)
=x(x−12)+16(x−12)
=(x+16)(x−12)
\(x^2+4x-192\)
\(\left(x^2-12x\right)+\left(16x-192\right)\)
\(=x\left(x-12\right)+16\left(x-12\right)\)
\(=\left(x+16\right)\left(x-12\right)\)