Bài 10:
a) \(\dfrac{4}{7}+\dfrac{1}{7}\) \(=\dfrac{5}{7}\)
b) \(\dfrac{6}{5}+\dfrac{2}{3}=\dfrac{18}{15}+\dfrac{10}{15}=\dfrac{28}{15}\)
c) \(\dfrac{7}{6}+\dfrac{3}{4}=\dfrac{28}{24}+\dfrac{18}{24}=\dfrac{46}{24}=\dfrac{23}{12}\)
d) \(2+\dfrac{2}{5}=\dfrac{2}{1}+\dfrac{2}{5}=\dfrac{10}{5}+\dfrac{2}{5}=\dfrac{12}{5}\)
Bài 11:
a) \(\dfrac{4}{7}-\dfrac{1}{7}=\dfrac{3}{7}\)
b) \(\dfrac{6}{5}-\dfrac{2}{3}=\dfrac{18}{15}-\dfrac{10}{15}=\dfrac{8}{15}\)
c) \(\dfrac{7}{6}-\dfrac{3}{4}=\dfrac{28}{24}-\dfrac{18}{24}=\dfrac{10}{24}=\dfrac{5}{12}\)
d) \(\dfrac{5}{2}-2=\dfrac{5}{2}-\dfrac{2}{1}=\dfrac{5}{2}-\dfrac{4}{2}=\dfrac{1}{2}\)