Question

GIÚP MÌNH CÂU NÀY VS
P=\(\left(\frac{\sqrt{x}}{\sqrt{x}-1}-\frac{1}{x-\sqrt{x}}\right)chia\left(\frac{1}{1+\sqrt{x}}+\frac{2}{x-1}\right)\)
rút gọn P
tìm x đề p lớn hơn 0

 

Answer 1

\(P=\left(\frac{\sqrt{x}}{\sqrt{x}-1}-\frac{1}{x-\sqrt{x}}\right):\left(\frac{1}{\sqrt{x}+1}+\frac{2}{x-1}\right)\)với x >= 0 ; x khác 1 

\(=\left(\frac{x-1}{\sqrt{x}\left(\sqrt{x}-1\right)}\right):\left(\frac{\sqrt{x}+1}{\left(\sqrt{x}+1\right)\left(x-1\right)}\right)\)

\(=\frac{\sqrt{x}+1}{\sqrt{x}}:\frac{1}{x-1}=\frac{\left(\sqrt{x}+1\right)\left(x-1\right)}{\sqrt{x}}\)

số xấu vậy bạn, bạn kiểm tra lại đề nhé 

Answer 2

\(P=\left(\frac{\sqrt{x}}{\sqrt{x}-1}-\frac{1}{x-\sqrt{x}}\right):\left(\frac{1}{1+\sqrt{x}}+\frac{2}{x-1}\right)\)

\(P=\frac{\sqrt{x}-1}{\sqrt{x}\left(\sqrt{x}-1\right)}:\frac{\sqrt{x}-1+2}{\left(\sqrt{x}+1\right)\left(\sqrt{x}-1\right)}\)

\(P=\frac{\sqrt{x}-1}{\sqrt{x}\left(\sqrt{x}-1\right)}.\frac{\left(\sqrt{x}+1\right)\left(\sqrt{x}-1\right)}{\sqrt{x}+1}\)

\(P=\frac{\sqrt{x}-1}{\sqrt{x}}\)

Answer 3

ý quên tách x - 1 rồi =))))