\(=>RTd=\dfrac{12}{0,5}=3R1+R2=>R2=24-3R1\left(om\right)\)
\(=>I=I1=I2=I3=0,5A\)
\(=>\)\(3U1=U2=>3R1=R2=>3R1=24-3R1=>R1=4\left(om\right)\)
\(=>R3=2.4=8\left(om\right)\)
\(=>R2=24-3.4=12\left(om\right)\)
\(=>U1=4.0,5=2V\)
\(=>U2=12.0,5=6V\)
\(=>U3=8.0,5=4V\)
Đúng 1
Bình luận (0)
