giúp mình câu 16
\(n_{NO}=a\left(mol\right).n_{N_2O}=b\left(mol\right)\)
\(n_{hh}=a+b=0.1\left(mol\right)\)
\(m_{hh}=30a+46b=19.8\cdot0.1\cdot2=3.96\left(g\right)\)
\(\Rightarrow a=0.04,b=0.06\)
Bảo toàn e :
\(n_{Fe}=\dfrac{3\cdot0.04+0.06}{3}=0.06\left(mol\right)\)
\(m=0.06\cdot56=3.36\left(g\right)\)
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