= 1 x (1 - 1/2 + 1/2 - 1/3 +....+1/2002 - 1/2003)
= 1 x (1 - 1/2003)
= 1 x 2002/2003
= 2002/2003
bạn ghi đề nhé
= 1 x (1 - 1/2 + 1/2 - 1/3 +....+1/2002 - 1/2003)
= 1 x (1 - 1/2003)
= 1 x 2002/2003
= 2002/2003
\(=\frac{1}{2002}-\frac{1}{2003}+\frac{1}{2001}-\frac{1}{2002}+...+\frac{1}{2}-\frac{1}{3}+1-\frac{1}{2}\)
\(=1-\frac{1}{2003}=\frac{2002}{2003}\)