Question

giúp mình bài này với ạ,ghi rõ ra luôn ạ

Answer 1

quy đồng r khử mẫu là ok

Answer 2

\(ĐK:x\ne0;2\)

\(\Leftrightarrow\dfrac{x+2}{x}-\dfrac{2x+3}{2\left(x-2\right)}=0\)

\(\Leftrightarrow\dfrac{2\left(x-2\right)\left(x+2\right)-x\left(2x+3\right)}{2x\left(x-2\right)}=0\)

\(\Leftrightarrow2\left(x^2-4\right)-x\left(2x+3\right)=0\)

\(\Leftrightarrow2x^2-8-2x^2-3x=0\)

\(\Leftrightarrow-3x=8\Leftrightarrow x=-\dfrac{8}{3}\left(tm\right)\)

Answer 3

\(\dfrac{2\left(x-2\right)\left(x+2\right)}{2x\left(x-2\right)}=\dfrac{x\left(2x+3\right)}{2x\left(x-2\right)}\)

\(\Leftrightarrow\) \(2x^2-8=2x^2+3x\)

\(\Leftrightarrow-3x=8\\ \Leftrightarrow x=-\dfrac{8}{3}\)

Vậy S = \(\left\{-\dfrac{8}{3}\right\}\)