\(b,-\dfrac{2}{3}x+1,2=\left(-\dfrac{1}{2}\right)^2\\ =>-\dfrac{2}{3}x+\dfrac{6}{5}=\dfrac{1}{4}\\ =>-\dfrac{2}{3}x=\dfrac{1}{4}-\dfrac{6}{5}\\ =>-\dfrac{2}{3}x=\dfrac{5-6.4}{20}\\ =>-\dfrac{2}{3}x=-\dfrac{19}{20}\\ =>x=\left(-\dfrac{19}{20}\right):\left(-\dfrac{2}{3}\right)\\ x=\dfrac{57}{40}\)
\(-\dfrac{2}{3}x+1,2=\left(-\dfrac{1}{2}\right)\)
\(-\dfrac{2}{3}x+\dfrac{6}{5}=\left(-\dfrac{1}{2}\right)\)
\(-\dfrac{2}{3}x\) \(=\left(-\dfrac{1}{2}\right)-\dfrac{6}{5}\)
\(-\dfrac{2}{3}x\) \(=-\dfrac{17}{10}\)
\(=>\dfrac{2}{3}x\) \(=\dfrac{17}{10}\)
\(x\) \(=\dfrac{17}{10}
:
\dfrac{2}{3}\)
\(x\) \(=\dfrac{51}{20}\)
`!`
`-2/3 x+ 1,2=(-1/2)^2`
`=> -2/3 x+ 6/5 = 1/4`
`=> -2/3 x=1/4-6/5`
`=> -2/3 x= 5/20-24/20`
`=> -2/3 x= -19/20`
`=>x=-19/20 : (-2/3)`
`=>x=-19/20 xx (-3/2)`
`=>x=57/40`
giúp mình bài 2.4 thôi ạ , mình cần gấp ạ
