\(25\%x-\frac{7}{8}+x=\frac{2}{3}x\)
<=> \(\frac{1}{4}x-\frac{7}{8}+1x=\frac{2}{3}x\)
<=> \(\frac{1}{4}x+1x-\frac{2}{3}x=\frac{7}{8}\)
<=> \(x\left(\frac{1}{4}+1-\frac{2}{3}\right)=\frac{7}{8}\)
<=> \(x\cdot\frac{7}{12}=\frac{7}{8}\)
<=> \(x=\frac{12}{8}=\frac{3}{2}\)
Bài làm:
Ta có: \(25\%x-\frac{7}{8}+x=\frac{2}{3}x\)
\(\Leftrightarrow\frac{x}{4}+x-\frac{2}{3}x=\frac{7}{8}\)
\(\Leftrightarrow\frac{7}{12}x=\frac{7}{8}\)
\(\Leftrightarrow x=\frac{3}{2}\)
