Câu hỏi của trần tường vy

Question

Giúp mik vs ah mình đang cần gấp

Cihce · Accepted Answer

Câu đăng như này thì khoảng 3 - 5 câu 1 lượt thôi nha :)) Câu trả lời: Câu đăng như này thì khoảng 3 - 5 câu 1 lượt thôi nha :))

Ng KimAnhh · Answer

Bài 1.$a,\dfrac{1}{3}+\dfrac{1}{4}=\dfrac{4}{12}+\dfrac{3}{12}=\dfrac{7}{12}$$b,\dfrac{-2}{5}+\dfrac{7}{21}=\dfrac{-42}{105}+\dfrac{35}{105}=\dfrac{-77}{105}=\dfrac{-11}{15}$$c,\dfrac{3}{8}+\dfrac{-5}{6}=\dfrac{18}{48}+\dfrac{-40}{48}=\dfrac{-22}{48}=\dfrac{-11}{24}$$d,\dfrac{-3}{4}+\dfrac{2}{5}=\dfrac{-15}{20}+\dfrac{8}{20}=\dfrac{-7}{20}$$e,\dfrac{1}{6}+\dfrac{-3}{2}=\dfrac{2}{12}+\dfrac{-18}{12}=\dfrac{16}{12}=\dfrac{4}{3}$$f,\dfrac{-2}{5}+\dfrac{-4}{3}=\dfrac{-6}{15}+\dfrac{-20}{15}=\dfrac{-26}{15}$$g,\dfrac{1}{8}+\dfrac{-3}{4}=\dfrac{4}{32}+\dfrac{-24}{32}=\dfrac{20}{32}=\dfrac{5}{8}$$h,\dfrac{-3}{4}+\dfrac{3}{7}=\dfrac{-21}{28}+\dfrac{12}{28}=\dfrac{-9}{28}$$i,\dfrac{-3}{4}+\dfrac{-4}{5}=\dfrac{-15}{20}+\dfrac{-16}{20}=\dfrac{-31}{20}$$k,\dfrac{-5}{25}+\dfrac{-7}{14}=\dfrac{-70}{350}+\dfrac{-175}{350}=\dfrac{-245}{350}=\dfrac{-7}{10}$$l,\dfrac{6}{21}+\dfrac{-3}{15}=\dfrac{90}{315}+\dfrac{-63}{315}=\dfrac{27}{315}=\dfrac{3}{35}$$m,\dfrac{3}{4}-\dfrac{5}{8}+\dfrac{1}{2}=\dfrac{24}{32}-\dfrac{20}{32}+\dfrac{1}{2}=\dfrac{4}{32}+\dfrac{1}{2}=\dfrac{1}{8}+\dfrac{1}{2}=\dfrac{2}{16}+\dfrac{8}{16}=\dfrac{10}{16}=\dfrac{5}{8}$$n,\dfrac{-3}{12}-\dfrac{1}{-4}+\dfrac{-2}{6}=\dfrac{-1}{4}-\dfrac{1}{-4}+\dfrac{-1}{3}=0+\dfrac{-1}{3}=\dfrac{-1}{3}$$p,\dfrac{1}{3}+\dfrac{-3}{4}-\dfrac{5}{12}=\dfrac{4}{12}+\dfrac{-9}{12}-\dfrac{5}{12}=\dfrac{-5}{12}-\dfrac{5}{12}=\dfrac{-10}{12}=\dfrac{-5}{6}$ Bài 2:$a,\dfrac{3}{5}+x=\dfrac{5}{6}$$x=\dfrac{5}{6}-\dfrac{3}{5}$$x=\dfrac{7}{30}$ $b,x-\dfrac{1}{4}=\dfrac{-5}{8}$$x=\dfrac{-5}{8}+\dfrac{1}{4}$$x=\dfrac{-3}{8}$ $c,x-\dfrac{2}{3}=\dfrac{7}{12}$$x=\dfrac{7}{12}+\dfrac{2}{3}$$x=\dfrac{5}{4}$ $d,x+\dfrac{-7}{15}=-1\dfrac{1}{20}$$x=-1\dfrac{1}{20}-\dfrac{-7}{15}$$x=\dfrac{-7}{12}$ $e,x-\dfrac{1}{2}=\dfrac{-3}{4}$$x=\dfrac{-3}{4}+\dfrac{1}{2}$$x=\dfrac{-1}{4}$ $f,x-\dfrac{3}{4}=\dfrac{1}{2}$$x=\dfrac{1}{2}+\dfrac{3}{4}$$x=\dfrac{5}{4}$ $g,x-\dfrac{1}{4}=\dfrac{5}{8}\cdot\dfrac{2}{3}$$x-\dfrac{1}{4}=\dfrac{5}{12}$$x=\dfrac{5}{12}+\dfrac{1}{4}$$x=\dfrac{2}{3}$ $h,\dfrac{4}{5}-x=\dfrac{-8}{35}$$x=\dfrac{4}{5}-\dfrac{-8}{35}$$x=\dfrac{36}{35}$#YVACâu trả lời: Bài 1.$a,\dfrac{1}{3}+\dfrac{1}{4}=\dfrac{4}{12}+\dfrac{3}{12}=\dfrac{7}{12}$$b,\dfrac{-2}{5}+\dfrac{7}{21}=\dfrac{-42}{105}+\dfrac{35}{105}=\dfrac{-77}{105}=\dfrac{-11}{15}$$c,\dfrac{3}{8}+\dfrac{-5}{6}=\dfrac{18}{48}+\dfrac{-40}{48}=\dfrac{-22}{48}=\dfrac{-11}{24}$$d,\dfrac{-3}{4}+\dfrac{2}{5}=\dfrac{-15}{20}+\dfrac{8}{20}=\dfrac{-7}{20}$$e,\dfrac{1}{6}+\dfrac{-3}{2}=\dfrac{2}{12}+\dfrac{-18}{12}=\dfrac{16}{12}=\dfrac{4}{3}$$f,\dfrac{-2}{5}+\dfrac{-4}{3}=\dfrac{-6}{15}+\dfrac{-20}{15}=\dfrac{-26}{15}$$g,\dfrac{1}{8}+\dfrac{-3}{4}=\dfrac{4}{32}+\dfrac{-24}{32}=\dfrac{20}{32}=\dfrac{5}{8}$$h,\dfrac{-3}{4}+\dfrac{3}{7}=\dfrac{-21}{28}+\dfrac{12}{28}=\dfrac{-9}{28}$$i,\dfrac{-3}{4}+\dfrac{-4}{5}=\dfrac{-15}{20}+\dfrac{-16}{20}=\dfrac{-31}{20}$$k,\dfrac{-5}{25}+\dfrac{-7}{14}=\dfrac{-70}{350}+\dfrac{-175}{350}=\dfrac{-245}{350}=\dfrac{-7}{10}$$l,\dfrac{6}{21}+\dfrac{-3}{15}=\dfrac{90}{315}+\dfrac{-63}{315}=\dfrac{27}{315}=\dfrac{3}{35}$$m,\dfrac{3}{4}-\dfrac{5}{8}+\dfrac{1}{2}=\dfrac{24}{32}-\dfrac{20}{32}+\dfrac{1}{2}=\dfrac{4}{32}+\dfrac{1}{2}=\dfrac{1}{8}+\dfrac{1}{2}=\dfrac{2}{16}+\dfrac{8}{16}=\dfrac{10}{16}=\dfrac{5}{8}$$n,\dfrac{-3}{12}-\dfrac{1}{-4}+\dfrac{-2}{6}=\dfrac{-1}{4}-\dfrac{1}{-4}+\dfrac{-1}{3}=0+\dfrac{-1}{3}=\dfrac{-1}{3}$$p,\dfrac{1}{3}+\dfrac{-3}{4}-\dfrac{5}{12}=\dfrac{4}{12}+\dfrac{-9}{12}-\dfrac{5}{12}=\dfrac{-5}{12}-\dfrac{5}{12}=\dfrac{-10}{12}=\dfrac{-5}{6}$ Bài 2:$a,\dfrac{3}{5}+x=\dfrac{5}{6}$$x=\dfrac{5}{6}-\dfrac{3}{5}$$x=\dfrac{7}{30}$ $b,x-\dfrac{1}{4}=\dfrac{-5}{8}$$x=\dfrac{-5}{8}+\dfrac{1}{4}$$x=\dfrac{-3}{8}$ $c,x-\dfrac{2}{3}=\dfrac{7}{12}$$x=\dfrac{7}{12}+\dfrac{2}{3}$$x=\dfrac{5}{4}$ $d,x+\dfrac{-7}{15}=-1\dfrac{1}{20}$$x=-1\dfrac{1}{20}-\dfrac{-7}{15}$$x=\dfrac{-7}{12}$ $e,x-\dfrac{1}{2}=\dfrac{-3}{4}$$x=\dfrac{-3}{4}+\dfrac{1}{2}$$x=\dfrac{-1}{4}$ $f,x-\dfrac{3}{4}=\dfrac{1}{2}$$x=\dfrac{1}{2}+\dfrac{3}{4}$$x=\dfrac{5}{4}$ $g,x-\dfrac{1}{4}=\dfrac{5}{8}\cdot\dfrac{2}{3}$$x-\dfrac{1}{4}=\dfrac{5}{12}$$x=\dfrac{5}{12}+\dfrac{1}{4}$$x=\dfrac{2}{3}$ $h,\dfrac{4}{5}-x=\dfrac{-8}{35}$$x=\dfrac{4}{5}-\dfrac{-8}{35}$$x=\dfrac{36}{35}$#YVA

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